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The given reaction can occur in the presence of :
(a) Bromine water                     (b) \mathrm{Br}_{2}$ in $\mathrm{CS}_{2}, 273 \mathrm{~K}
(c) \mathrm{Br}_{2} / \mathrm{FeBr}_{3}                      (d) \mathrm{Br}_{2}$ in $\mathrm{CHCl}_{3}, 273 \mathrm{~K}
Choose the correct answer from the options given below:
Option: 1 \mathrm{\text { (b)\ and }(d) \text { only }}
Option: 2 \mathrm{\text { (a)\ and\ (c)\ only }}
Option: 3 \mathrm{(b),(c) \operatorname{and}(d) \text { only }}
Option: 4 \mathrm{(a),(b) \text { and }(d) \text { only }}

Answers (1)

best_answer

As we have learnt,

Phenol on reaction with Bromine water forms 2,4,6-Tribromophenol.



This is attributed to the polarity of water which facilitates the formation of Phenoxide ion which is highly activated toward Electrophilic Substitution.

Monobromination can be carried out using non-polar solvents like \mathrm{CS_{2}} or \mathrm{CCl_{4}} and solvents with low dielectric constant \mathrm{\left ( CHCl__{3} \right )}


It Is to be noted that Lewis acids are not prefered in the reaction because Phenol itself forms a complex with lewis acids and gets deactivated towards electrophilic substitution.

Hence, the correct answer is option (1)

Posted by

sudhir.kumar

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