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The graph between the log K versus 1/T is a straight line. The intercept of the line on y axis is.

Option: 1

\mathrm{\log \left(\frac{E a}{2,303 R}\right)}


Option: 2

\log \mathrm{Ao}


Option: 3

\log \mathrm{RT}


Option: 4

None of the above


Answers (1)

best_answer


\mathrm{K}=\mathrm{A}_0 \mathrm{e}^{-\mathrm{Ea} / \mathrm{RT}}
Taking logarithm of both sides,
\begin{aligned} 2.303 \log \mathrm{K}=2.303 \log \mathrm{A}_0-\mathrm{Ea} / \mathrm{RT} \\ \end{aligned}

\mathrm{ \log \mathrm{K}=\log \mathrm{Ao}-\frac{E a}{2.303 R} \times \frac{1}{T}}
Clearly, it is a straight line (y=mx+c) graph between log K vs 1/T
Intercept on y-axis \mathrm{=\log \mathrm{Ao}}

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Ritika Kankaria

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