The group consists of 8 Indians and 10 Americans, and 10 members will be chosen. How will the members be chosen so that there are at least 5 Americans and at most 4 Indians?
22761
22760
23761
23760
Given that,
The group consists of 8 Indians and 10 Americans.
Case I: 6 Americans and 4 Indians can be selected
The number of ways is given by,
Case II: 7 Americans and 3 Indians can be selected
The number of ways is given by,
Case III: 8 Americans and 2 Indians can be selected
The number of ways is given by,
Case IV: 9 Americans and 1 Indian can be selected
The number of ways is given by,
Case V: 10 Americans are selected
The number of ways is given by,
Therefore, the total number of ways of selecting the members = 14700 + 6720 + 1260 + 80+1 = 22761 ways.
Study 40% syllabus and score up to 100% marks in JEE