Get Answers to all your Questions

header-bg qa

The half life period of a radioactive substance is 60 days. The time taken for \frac{7}{8} th of its original mass to disintegrate will be :
 

Option: 1

120 days


Option: 2

130 days


Option: 3

180 days

 


Option: 4

20 days


Answers (1)

best_answer

\mathrm{T_{1 / 2}=60 days}

\mathrm{N_t=N_0-\frac{7}{8} N_0=\frac{1}{8} N_0\: \: (Given)}

\mathrm{N_t \rightarrow No \, of \: nuclei\: at \: time\: t}

\mathrm{N_0 \rightarrow No\: of \: nuclei \: initially }

\mathrm{N_t=N_0 2^{-t / T_{1 / 2}} }

\mathrm{\frac{1}{8}=\frac{1}{2^{t / T_{1 / 2}}} }

\mathrm{t_{T_{1 / 2}}=3 }

\mathrm{t=180 \text { days } }

Hence 3 is correct option.







 

Posted by

admin

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE