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  • The increasing order of the boiling points for the following compounds is : Option: 1  (III) < (IV) < (II) <

The increasing order of the boiling points for the following compounds is :
Option: 1  (III) < (IV) < (II) < (I)
Option: 2 (IV) < (III) < (I) < (II)
Option: 3  (II) < (III) < (IV) < (I)
Option: 4 (III) < (II) < (I) < (IV)  
 

Answers (1)

best_answer

The increasing order of boiling point is

\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OCH}_{3}<\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{CH}_{3}<\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Cl}<\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}

in C2?H5?OH (i) C-O bond is polar & form hydrogen bonding in H2?O

 in C2?H5?Cl → C-Cl bond is polar but less than that of C-O bond
so boiling point of C2?H5?Cl is less than that of C2?H5?OH
in C2?H5?OCH3?   , the C-O bond is polar but the weak polarity of ethers do not appreciably affect their boiling points

And alkane has the least boiling point than above compounds.

Answer: (1)

Posted by

vishal kumar

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