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  • The ionisation constant of  in water is 6*10-10  at 25 degr

The ionisation constant of NH_{4}^{+} in water is 6*10-10  at 25 degree Celcius. The rate constant for reaction of NH_{4}^{+} and OH^{-} to form NH_{3} and H_{2}O at 25 degree Celcius is 3.5*1010  l/mol.sec. Calculate the rate constant for proton transfer from water to NH_{3}

Option: 1

6.66\times 10^{3}


Option: 2

5.83\times 10^{5}


Option: 3

6.66\times 10^{6}


Option: 4

7.64\times 10^{5}


Answers (1)

best_answer

The reactions according to the question will be:

\mathrm{NH}_{3}+\mathrm{H}_{2} \mathrm{O} \stackrel{K_{f}}{\rightleftharpoons_{K_{b}}} \mathrm{NH}_{4}^{+}+\mathrm{OH}^{-}        K_{\mathrm{b}}=3.5 \times 10^{10}

\mathrm{NH}_{4}^{+}+\mathrm{H}_{2} \mathrm{O} \rightleftharpoons \mathrm{NH}_{4} \mathrm{OH}+\mathrm{H}^{+} ; \quad K_{\mathrm{acid}}=6 \times 10^{-10}

\begin{aligned} K_{\mathrm{base}} &=\frac{K_{f}}{K_{b}} \\ \text { Also, } & K_{\mathrm{base}}=\frac{K_{w}}{K_{\mathrm{acid}}} \end{aligned}

\frac{K_{f}}{3.5 \times 10^{10}}=\frac{10^{-14}}{6 \times 10^{-10}}

K_{f} = 5.83\times 10^{5}

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