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The ionisation potential of hydrogen atom is 13.6 \mathrm{~V}. The energy required to remove an electron from the second orbit of hydrogen will be:
 

Option: 1

27.4 \mathrm{eV}


Option: 2

16.6 \mathrm{eV}
 


Option: 3

3.4 \mathrm{eV}
 


Option: 4

10.2 \mathrm{eV}

 


Answers (1)

Energy of an electron in the nth orbit of the hydrogen atom is  \mathrm{E_n=-\frac{13.6}{n^2} \mathrm{eV}}

Energy of electron in second orbit is \mathrm{E_2=-\frac{13.6}{2^2} \mathrm{eV}=-\frac{13.6}{4} \mathrm{eV}=-3.4 \mathrm{eV}}

Energy required to remove an electron from second orbit is

\begin{aligned} & \mathrm{E=E_{\infty}-E_2} \\ & \mathrm{E=0-(-3.4) \mathrm{eV} \text { or } \mathrm{E}=3.4 \mathrm{eV} }\end{aligned}

Hence, the required energy is 3.4 \mathrm{eV}.

Posted by

Ramraj Saini

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