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The IUPAC name of the following comound is:
Option: 1 5-Bromo-3-methylcyclopentanoic acid
Option: 2 4-Bromo-2-methylcyclopentane carboxylic acid
Option: 3 3-Bromo-5-methylcyclopentanoic acid
Option: 4 3-Bromo-5-methylcyclopentane carboxylic acid

Answers (1)


-COOH group has more seniority than others.

At 2 branched carbon preferred.

At 4 there is Br

So, counting will be

So, IUPAC Name

4-Bromo-2-methylcyclopentane carboxylic acid

Therefore, the correct option is (2).

Posted by

Kuldeep Maurya

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