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The length of a metallic wire is increased by 20% and its area of cross section is reduced by 4%. The percentage
change in resistance of the metallic wire is ______

Option: 1

25


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\begin{aligned} & R=\frac{\rho l}{A} \\ & R^{\prime}=\frac{\rho \times 1.21}{0.96 \mathrm{~A}}=\frac{10}{8} \times R=1.25 R \end{aligned}\\

It means 25 \% increase in Resistance.

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vinayak

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