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The magnetic field between the plate of a capacitor where r>R is given by (where r is the distance from the axis of plates and R is the radius of each plate of capacitor)

Option: 1

\frac{\mu_0 i_D r}{2 \pi R^2}


Option: 2

\frac{\mu_0 i_D}{2 \pi R}


Option: 3

\frac{\mu_0 i_D}{2 \pi r}


Option: 4

Zero


Answers (1)

best_answer

Using Ampere circuit law,
\mathrm{\oint \overrightarrow{\mathbf{B}} \cdot \overrightarrow{\mathbf{d l}}=\mu_0 i_D}
\mathrm{\, \, or\, \ B 2 \pi r=\mu i_D \, \, or \, \, B=\mu_0 i_D / 2 \pi r}

Posted by

shivangi.bhatnagar

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