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The magnetic field due to a long straight current carrying conductor of radius $\mathrm{R}$ , when $\mathrm{r>R}$ [ $\mathrm{r \rightarrow}$ distance between the point and the axis of wire] proportional to -
Option: 1
$\mathrm{r}$

Option: 2
$\mathrm{r^{-1} }$

Option: 3
$\mathrm{r^2 }$

Option: 4
$r^{-2}$

Answers (1)

best_answer

$\mathrm{\int \bar{B} \cdot d \bar{e}=\mu \cdot \int \bar{J} \cdot d s }$
$\mathrm{B \cdot 2 \pi r=\mu }$ { current crossing the bounded surface

when $\mathrm{r>R }$ , current crossing bounded surface is $\mathrm{I }$

$\mathrm{ B \cdot 2 \pi \ r =\mu_0 I }$

$\mathrm{ B=\frac{\mu_0}{4 \pi} \frac{2 I}{r }$

$\mathrm{ B \propto \frac{1}{r} \quad}$ .

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