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The magnetic field in a plane electromagnetic wave is given by \mathrm{\mathrm{B}_{\mathrm{y}}=2 \times 10^{-7} \sin \left(0.5 \times 10^3 \mathrm{x}+1.5 \times 10^{11} \mathrm{t}\right) \mathrm{T}}. The electromagnetic wave is:
 

Option: 1

a visible light

 


Option: 2

an infrared rays
 


Option: 3

a microwave
 


Option: 4

a radio wave


Answers (1)

best_answer

\mathrm{\mathrm{B}_{\mathrm{y}}=2 \times 10^{-7} \sin \left(0.5 \times 10^3 \mathrm{x}+1.5 \times 10^{11} \mathrm{t}\right) \mathrm{T}}

Comparing with the standard equation, we get

\mathrm{\mathrm{B}_{\mathrm{y}}=\mathrm{B}_0 \sin (\mathrm{kx}+\omega \mathrm{t}) }

\mathrm{\mathrm{k}=0.5 \times 10^3 }

\mathrm{ \Rightarrow \lambda=\frac{2 \pi}{0.5 \times 10^3}=0.01256 \mathrm{~m}}

The wavelength range of microwaves is \mathrm{ 10^{-3} \mathrm{~m}\: to\: 0.3 \mathrm{~m}}. The wavelength of this wave lies between \mathrm{ 10^{-3} \mathrm{~m}\: to \: 0.3 \mathrm{~m}}, so the equation represents a microwaves.

Hence option 3 is correct.

Posted by

Sayak

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