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The magnetic flux linked with a coil of N turns of area of cross section A held with its plane parallel to the field B is:

Option: 1

\mathrm{\frac{NAB}{2}}


Option: 2

\mathrm{NAB}


Option: 3

\mathrm{\frac{NAB}{4}}


Option: 4

\mathrm{zero}


Answers (1)

best_answer

Magnetic flux linked with a coil \mathrm{\phi=\mathrm{NBA} \cos \theta}

Since the magnetic field B is parallel to the area A, i.e.,\mathrm{\theta=90^{\circ}}

\mathrm{\therefore \phi=0}

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