Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • The magnetic flux through a coil perpendicular to its plane is varying according to the relation <img alt="\phi=\left(5 \mathrm{t}^{3}+4 \mathrm{t}^{2}+2 \mathrm{t}-5\right)" src="https://entrancec

The magnetic flux through a coil perpendicular to its plane is varying according to the relation \phi=\left(5 \mathrm{t}^{3}+4 \mathrm{t}^{2}+2 \mathrm{t}-5\right) Weber. If the resistance of the coil is 5 \mathrm{ohm}, then the induced current through the coil at t=2 s will be,
 

Option: 1

15.6 \mathrm{~A}


Option: 2

16.6 \mathrm{~A}


Option: 3

17.6 \mathrm{~A}


Option: 4

18.6 \mathrm{~A}


Answers (1)

best_answer

\mathrm{\phi = 5t^{3}+4t^{2}+2t-5}
\mathrm{e= \left |\frac{d\phi}{dt} \right |= 15t^{2}+8t+2}

\mathrm{at\, t= 2s,}
\mathrm{i R= \left | \frac{d\phi}{dt}\right |= 60+16+2= 78}
\mathrm{i= \frac{78}{5}= 15.6\, A}
The correct option is (1)
 

Posted by

shivangi.bhatnagar

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

Calculate JEE Main 2025 rank using predictor tool for admission to top IITs, NITs, IIITs
anam-khan

NTA drops 1 out of 9 flagged errors from JEE Mains final answer key 2025
anam-khan

Consumer protection watchdog warns coaching centres against misleading ads ahead of IIT-JEE Main results

Latest Question