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  • The magnetic moment of a transition metal compound has been calculated to be 3.87 B.M. The metal ion isOption: 1 <img alt="\mathrm{Cr}^{2+}" src="htt

The magnetic moment of a transition metal compound has been calculated to be 3.87 B.M. The metal ion is

Option: 1

\mathrm{Cr}^{2+}


Option: 2

\mathrm{T i^{2+}}


Option: 3

\mathrm{V}^{2+}


Option: 4

\mathrm{Mn}^{2+}


Answers (1)

best_answer

\sqrt{\mathrm{n}(\mathrm{n}+2)}=3.87

\mathrm{n}=3=\mathrm{no} \text {. of unpaired } \mathrm{e}^{-}

\mathrm{Cr}^{2+}=[\mathrm{Ar}] 3 \mathrm{~d}^4
\mathrm{Tr}^{-2+}=[\mathrm{Ar}] 3 \mathrm{~d}^2
\mathrm{~V}^{2+}=[\mathrm{Ar}] 3 \mathrm{~d}^3
\mathrm{Mn}^{2+}=[\mathrm{Ar}] 3 \mathrm{~d}^5

Posted by

Gautam harsolia

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