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The maximum amplitude for an amplitude modulated wave is found to be 12V while the minimum amplitude is found to be 3V. The modulation index is 0.6x where x is ______.
 

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\begin{aligned} &\text { Maximum \: amplitude}=V_{\text {max }}=12\\ \end{aligned}

\begin{aligned} &\text { Minimum amplitude }=V_{\text {min }}=3\\ \end{aligned}

\begin{aligned} &\mu =\frac{V_{\max }-V_{\min }}{V_{\max }+V_{\min }}=\frac{9}{15}\\ &\mu =0.6\\ &\therefore x=1 \end{aligned}

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