The mean and variance of a Poisson distribution are 2 and 1 respectively. Find the probability that there will be at least two successes in 5 trials.
0.301
0.408
0.556
0.624
To find the probability that there will be at least two successes in 5 trials in a Poisson distribution with mean 2, we can use the cumulative probability function of the Poisson distribution.
Let X be the random variable representing the number of successes in 5 trials. The Poisson distribution with mean (lambda) is given by:
Where, number of successes
To find the probability of at least two successes ( 2 or more) in 5 trials, we need to sum the probabilities of getting 2,3,4, or 5 successes.
P( at least two successes)
- Exactly two successes:
- Exactly three successes:
- Exactly four successes:
- Exactly five successes:
The sum of these probabilities is:
So, the probability that there will be at least two successes in 5 trials in the given Poisson distribution is approximately
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