Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • The mean intensity of radiation on the surface of the sun is about 108 W/m2. The rms value of the corresponding magnetic field is closest to:

The mean intensity of radiation on the surface of the sun is about 108 W/m2. The RMS value of the corresponding magnetic field is closest to:

Answers (1)

Intensity of EM wave -

I = \frac{1}{2} \epsilon _{o} E_{o}^{2}c

- wherein

\epsilon _{o} = Permittivity of free space

E _{o} = Electric field amplitude

c = Speed of light in vacuum

 

I = 108 w/m2

I =\frac{1}{2} \epsilon _{o} E_{o}^{2}c= \varepsilon_{0}.CE^{2}rms............1

E_{rms} = CB_{rms}...........2

from 1 and 2

I=\varepsilon _{0}C^{3}B^{2}_{rms}

B_{rms} = \sqrt{\frac{I}{\varepsilon _{0}C^{3}}}= \sqrt{\frac{10^8}{8.85\times 10^{-12}\times \left ( 3\times 10^{8} \right )^{3}}}\approx 10^{-4}T

Posted by

lovekush

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2024 session 2 result date announced; Steps to check NTA session 2 scores
anam-khan

JEE Main 2024 session 2 final answer key soon at jeemain.nta.ac.in; result on April 25
anam-khan

JEE Main 2024 Session 2: Last day to challenge answer key today

Latest Question