Kinetic Energy is related to pressure as:

\begin{aligned} K . E &=\frac{3 R T}{2} \\ &=\frac{3 P V}{2} \\ \frac{K . E}{V} &=\frac{3 P}{2} \end{aligned}

Answers (1)

Kinetic energy of a gas due to translation per mole -

E= \frac{3}{2}PV

= \frac{3}{2}RT
 

- wherein

R = Universal gas constant

T = temperature of gas

 

 E=\frac{3}{2}nRT=\frac{3}{2}PV

\therefore P=\frac{2E}{3V} 

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