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The modulation index for an A.M. wave having maximum and minimum peak-to-peak voltages of 14 mV and 6 mV respectively is:

Option: 1

0.4


Option: 2

0.6


Option: 3

0.2


Option: 4

1.4


Answers (1)

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\begin{aligned} \mu=\text { Modulating index } & =\frac{A_{\max }-A_{\min }}{A_{\max }+A_{\min }} \\ & =\frac{14-6}{14+6} \\ & =0.4 \end{aligned}

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