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The molarity of HNO3 in a sample which has density 1.4 g/mL and mass percentage of 63% is ____ (in mol/L) (Molecular weight of HNO3 = 63)

Option: 1

14


Option: 2

15


Option: 3

12


Option: 4

10


Answers (1)

best_answer

\mathrm{63\%\:w/w\: \rightarrow \: HNO_{3}\: solution}

Let, mass of solution be 100g

\therefore Mass of HNO3 is 63 g

\therefore Moles of HNO3 is 1

\:Now, \:volume \:of \:solution \:=\frac{100}{1.4} ml = \frac{1}{14} \: litres

Molarity = \frac{1}{\frac{1}{14}}=\:14

 

Posted by

Sanket Gandhi

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