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  • The molecular orbital electronic configuration of   is represented as follows:<str

The molecular orbital electronic configuration of O_{2}  is represented as follows:

Option: 1

\sigma 1s^{2}\sigma^{*}1s^{2}\sigma 2s^{2}\sigma^{*} 2s^{2}\sigma2p_{x}^{2}\pi 2p_{x}^{2}\pi 2p_{y}^{2}\pi ^{*}2p_{x}^{1}\pi ^{*}2p_{y}^{1}


Option: 2

\sigma 1s^{2}\sigma ^*1s^{2}\sigma 2s^{2}\sigma ^*2s^2\sigma2p_{z}^{2}\pi 2p_{x}^{2}\pi 2p_{y}^{2}\pi ^{*}2p_{x}^{1}\pi ^{*}2p_{y}^{1}\sigma ^{*}2p_{z}


Option: 3

\sigma 1s^{2}\sigma ^{*} 1s^{2}\sigma2s^{2}\sigma ^{*}2s^{2}\pi 2p_{x}^{2}\pi 2p_{y}^{2}\sigma 2p_{z}^{2}\pi ^{*}2p_{x}^{1}\pi ^{*}2p_{y}^{1}


Option: 4

\sigma 1s^{2}\sigma ^{*} 1s^{2}\sigma2s^{2}\sigma ^{*}2s^{2}\pi 2p_{x}^{2}\pi 2p_{y}^{2}\sigma 2p_{z}^{2}\pi ^{*}2p_{x}^{1}\pi ^{*}2p_{y}^{1}\sigma ^{*}2p_{z}


Answers (1)

best_answer

Electronic configuration of molecules having electrons greater than 14 is:

\sigma 1s\ \sigma^{*}1s\ \sigma 2s\ \sigma^{*}2s\ \sigma2p_{z}\ \pi 2p_{x}\ \pi 2p_{y}\ \pi ^{*}2p_{x}\ \pi ^{*}2p_{y}\ \sigma ^{*}2p_{z}

Since the total number of electrons in oxygen molecule is 16, the molecular orbital electronic configuration would be:

\sigma 1s^{2}\ \sigma^*1s^{2}\ \sigma 2s^{2}\ \sigma ^*2s^2 \ \sigma2p_{z}^{2}\ \pi 2p_{x}^{2}\ \pi 2p_{y}^{2}\ \pi ^{*}2p_{x}^{1} \ \pi ^{*}2p_{y}^{1}

Hence, option number (2) is correct.

Posted by

Gautam harsolia

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