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  • The most common oxidation state of Lanthanoid elements is +3. Which of the following is likely to deviate easily from +3 oxidation state?Option: 1 <i

The most common oxidation state of Lanthanoid elements is +3. Which of the following is likely to deviate easily from +3 oxidation state?

Option: 1

\mathrm{Ce} \text { (At. No. 58) }


Option: 2

\mathrm{La} \text { (At. No. 57) }


Option: 3

\mathrm{Lu} \text { (At. No. 71) }


Option: 4

\mathrm{Gd} \text { (At. No. 64) }


Answers (1)

best_answer

Electronic configuration of Ce is \mathrm{\text { [Xe] } 4 f^{1} 5 d^{1} 6 s^{2}}

\therefore \mathrm{Ce^{4+}} has a noble gas configuration

Thus, \mathrm{Ce^{3+}} is likely to deviate to its (+4) oxidation state.

Hence, Option(1) is correct.

Posted by

Shailly goel

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