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  • The number density of free electrons in copper is nearly <img alt="8 \times 10^{28} \mathrm{~m}^{-3}" src="https://entrancecorner.oncodecogs.com/gif.latex?8%20%5Ctimes%2010%5E%7B28%7D%20%5Cmathrm%7

The number density of free electrons in copper is nearly 8 \times 10^{28} \mathrm{~m}^{-3}.  A copper wire has its area of cross section =2 \times 10^{-6} \mathrm{~m}^{2} and is carrying a current of 3.2 \mathrm{~A}.The drift speed of the electrons is______ \times 10^{-6} \mathrm{~ms}^{-1}

Option: 1

125


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\mathrm{I}= neAvd

\Rightarrow 3.2=8 \times 10^{28} \times 1.6 \times 10^{-19} \times 2 \times 10^{-6}\left(\mathrm{v}_{\mathrm{d}}\right)

\Rightarrow \mathrm{v}_{\mathrm{d}}=\frac{1}{8 \times 10^{-6} \times 10^{9}}

\Rightarrow \mathrm{v}_{\mathrm{d}}=125 \times 10^{-6} \mathrm{~m} / \mathrm{s}

Posted by

Sanket Gandhi

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