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The number of bridged oxygen atoms present in compound B formed from the following reactions is

\mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2} \stackrel{673 \mathrm{~K}}{\longrightarrow} \mathrm{A}+\mathrm{PbO}+\mathrm{O}_{2}

\mathrm{A} \stackrel{\text { Dimerise }}{\longrightarrow} \mathrm{B}

Option: 1

0


Option: 2

1


Option: 3

2


Option: 4

3


Answers (1)

best_answer

As we have learnt, 

Heating of \mathrm{PbNO_3} produces \mathrm{NO_2} apart from \mathrm{PbO} and \mathrm{O_2} as given below

\mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2} \stackrel{673 \mathrm{~K}}{\longrightarrow} 4 \mathrm{\underset{(A)}{NO_{2}}}+2 \mathrm{PbO}+\mathrm{O}_{2}

So, Option (1) is correct

Posted by

avinash.dongre

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