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15519582136261468787462.jpg The number of complex number z such that |z-i|=|z+i|=|z+1| is

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@mannika

We are given that, |z-i| = |z- (-i)| = |z- (-1)|

we know that in a complex plane, |z-a| represents distance of z from complex number a.

Now we are given, 3 points (0,1);(0,-1);(-1,0) from which distance of z is equal.But we know in a plane there exist only 1 point which are equidistant from these 3 points which is centroid of triangle made by these 3 points.

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Kshitij

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