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  • The number of isomers possible for  is:Option: 1 2Option: 2 4Option: 3 1Option: 4<

The number of isomers possible for \mathrm{[Pt(en)(NO_{2})_{2}]} is:
Option: 1 2
Option: 2 4
Option: 3 1
Option: 4 3

Answers (1)

best_answer

[\mathrm{Pt}(\mathrm{en})(\mathrm{NO_2})_2] does not show G.I. as well as optical isomerism - 

1. Geometrical isomerism does not show due to the steric hindrance of en ligand.

2. Optical isomerism does not show due to the presence of a plane of symmetry.

But, this complex will have three linkage isomers as follows -

\textup{1}. \left[\mathrm{Pt}(\mathrm{en})\left(\mathrm{NO}_{2}\right)_{2}\right]

\textup{2}.\left[\mathrm{Pt}(\mathrm{en})\left(\mathrm{NO}_{2}\right)(\mathrm{ONO})\right]

\textup{3}.\left[\mathrm{Pt}(\mathrm{en})(\mathrm{ONO})_{2}\right]

So, other than \left[\mathrm{Pt}(\mathrm{en})\left(\mathrm{NO}_{2}\right)_{2}\right] this, there are 2 isomer is possible.

Ans = 2

Therefore, the correct option is (1).

Posted by

Kuldeep Maurya

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