The orthocentre of the triangle formed by
(0,0), (8,0), (4,6) is
(4,8/3)
(3,4)
(4,3)
(-3,4)
a
Let ABC be the given triangle and the vertices be A(0,0), B(8,0), and C(4,6).
slope of BC=(6,0)/ (4-8) = -3/2.
Equation of line through A and
to BC is
(1)
And slope of CA=(6-0)/(4-0)=3/2
Equation of line through B and
to CA is
(2)
Solving (1) and (2), the orthocentre is (4,8/3),
Which is given in (a).
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