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  •  The oscillating magnetic field in a plane electromagnetic wave is given by <img alt="\mathrm{B_{y}=5 \times 10^{-6} \sin 1000 \pi\left(5 x-4 \times 10^{8} t\right) T}" src="/latex-image/

 The oscillating magnetic field in a plane electromagnetic wave is given by \mathrm{B_{y}=5 \times 10^{-6} \sin 1000 \pi\left(5 x-4 \times 10^{8} t\right) T} The amplitude of electric field will be : 

Option: 1

\mathrm{15 \times 10^{2} V_{m^{-1}}}


Option: 2

\mathrm{5 \times 10^{-6} \mathrm{Vm}^{-1}}


Option: 3

\mathrm{16 \times 10^{12} \mathrm{Vm}^{-1}}


Option: 4

\mathrm{4 \times 10^{2} \mathrm{Vm}^{-1}}


Answers (1)

best_answer

\mathrm{ By =5 \times 10^{-6} \sin \left(1000 \pi\left(5 x-4 \times 10^{8} t\right)\right) }

\mathrm{B_0 =5 \times 10^{-6} T}

We know that,

\mathrm{\frac{E_0}{B_0}=C }

\mathrm{E_0=15 \times 10^2 \frac{\mathrm{V}}{\mathrm{m}}}

Hence (1) is correct option.




 

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mansi

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