The particle is moving 5 times as fast as an electron, the ratio of the \lambdaof the particle to that of the electron is 1.878 x 10-4, then the mass of the particle is close to
Option: 1 9.7 x 10-28 kg
Option: 2 4.8 x 10-27 kg
Option: 3 1.2 x 10-28 kg  
Option: 4 9.1 x 10-31 kg

Answers (1)

\frac{\lambda_e}{\lambda_p} = \frac{\frac{h}{m_e v_e}}{\frac{h}{m_p v_p}} \\ \\

It is given that

\frac{\lambda_p}{\lambda_e} = 1.878 \times 10^{-4}

me = 9.109 x 10-31 kg

Also given that

Vp = 5 Ve

After putting the values - 

mp = 9.7 x 10-28 kg

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