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  • The p.d. across an instrument in an a.c. circuit of frequency f is V and the current flowing through it is I such that  <img alt="\mathrm{V=5 \cos \pi \mathrm{ft}(\mathrm{B}) \text {

The p.d. across an instrument in an a.c. circuit of frequency f is V and the current flowing through it is I such that 

\mathrm{V=5 \cos \pi \mathrm{ft}(\mathrm{B}) \text { volt and } \mathrm{I}=2 \sin (2 \pi \mathrm{ft}) \text { amp. }} The power dissipate in the instrument is ;

Option: 1

zero


Option: 2

10 watt


Option: 3

5 watt


Option: 4

2.5 watt


Answers (1)

best_answer

\mathrm{As \; V=5 \cos \pi \mathrm{ft}(2)=5 \sin (2 \pi \mathrm{ft}+\pi / 2)}

\mathrm{And \; \mathrm{I}=2 \sin (2\; \pi \mathrm{ft})}

\mathrm{\therefore } phase difference between V and I is \mathrm{\phi=\frac{\pi}{2}}

\mathrm{\text { Average power } P=V_{-1} I_{1 m} \times \cos \phi=0}

Posted by

Gaurav

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