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The product of the following reaction is 

\mathrm{CH_3-CH(Cl)-CH_3\xrightarrow[]{NaBH_4} ?}

Option: 1

CH_3-CH_3


Option: 2

CH_3-CH_2-CH_3


Option: 3

CH_3-CH=CH_2


Option: 4


Answers (1)

best_answer

The reaction will be:-\mathrm{CH_3-CH(Cl)-CH_3+NaBH_4\rightarrow CH_3-CH_2-CH_3}

Therefore, option (2) is correct.

Posted by

Divya Prakash Singh

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