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The radiation corresponding to n = 3 to n = 2 transition of hydrogen atoms falls on a metal surface to produce photoelectrons. These electrons are made to enter a magnetic field of 3 \times 10^{-4} T. If the radius of the largest circular path followed by these electrons is 10.0 mm. The work function of the metal is closest to

Option: 1

1.8 eV


Option: 2

1.1 eV


Option: 3

0.8 eV


Option: 4

1.6 eV


Answers (1)

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\\r=\frac{mv}{qB}=\frac{\sqrt{2m\: eV}}{eB}\\ V=\frac{B^2r^2e}{2m}=0.8V\\ \\\Delta E=E_2-E_3= 1.88 \:eV\\ \\ \phi =1.88eV-0.8eV=1.1eV

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vishal kumar

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