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The radius of electron's second stationary orbit in Bohr's atom is \mathrm{R}. The radius of 3 rd orbit will be

Option: 1

\frac{R}{3}


Option: 2

3 R


Option: 3

2.25 \mathrm{R}


Option: 4

9 \mathrm{R}


Answers (1)

best_answer

\mathrm{R}\, \alpha\, \frac{\mathrm{n}^{2}}{\mathrm{z}}

\frac{\mathrm{R}_{1}}{\mathrm{R}_{2}}=\left(\frac{\mathrm{n}_{1}}{\mathrm{n}_{2}}\right)^{2}=\left(\frac{2}{3}\right)^{2}

\mathrm{R}_{2}=\frac{9 \mathrm{R}}{4}=2.25 \mathrm{R}

Posted by

Pankaj Sanodiya

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