The radius of the circle having the lines as its normal and having size just sufficient to contain the circle _________.
(7.5)
(7.3)
(3.3)
(4.3)
The equation can be written on factorizing the L.H.S, as
Thus the equations of the two normals to the required circle are
Solving these, we get the co-ordinates of the centre as (-3,3 / 2). Again as the required circle just contains the circle
that is
This means that the required circle will touch the circle (1) internally. Let r be the radius of required circle. Also the radius of
the circle ( 1) is and its centre is (2,3 / 2).
Now the required circle will touch the circle (1) internally, if the distance between their centres is equal to the difference of their
radii that is,
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