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The radius of the coil of a tangent gavalnometer which has 10 turns is 0.1m. The current (in A) required to produce a deflection of 60o (B_H = 4\times 10^{-5} T) is

Option: 1

1.1


Option: 2

3


Option: 3

2.1


Option: 4

1.5


Answers (1)

best_answer

As we have learnt,

 

Tangent law -

When a small magnet is suspended in two uniform magnetic field B and B_{H} which are at right angles to each other

- wherein

The magnet comes to rest at an angle \Theta

 

 B = B_H\tan\theta \Rightarrow \frac{\mu_o ni}{2r} = B_H\tan\theta \\*\Rightarrow i = \frac{2rB_H\tan\theta}{\mu_o n} = \frac{2\times 0.1\times0.4\times 10^{-5}\times \sqrt{3}}{10\times 4\pi\times 10^{-7}} = 1.1A

 

Posted by

Kuldeep Maurya

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