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  • The radius of the second Bohr orbit for hydrogen atom is: (Planck’s Constant H = 6.6262×10−34 Js; mass of electron =9.1091×10−31 kg; charg

The radius of the second Bohr orbit for hydrogen atom is:
(Planck’s Constant H = 6.6262×10−34 Js; mass of electron =9.1091×10−31 kg; charge of electron e = 1.60210×10−19  C; permittivity of vacuum \epsilon _{0}  = 8.854185×10−12 kg−1m−3A2)

Option: 1

0.529


Option: 2

2.12


Option: 3

1.65


Option: 4

4.76


Answers (1)

best_answer

As we have learnt,

The Bohr radius of nth orbit is given as

r_{n}\, =\, 0..529\frac{n^{2}}{z}

Thus, n = 2, 

\mathrm{r_2=2.12 \ A^o}

Therefore, Option(2) is correct

Posted by

seema garhwal

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