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The rate constant \mathrm{(k)}  of a first order reaction is found out to be  \mathrm{0.0693 \mathrm{~min}^{-1}} . A reactant having initial concentration of \mathrm{20 \mathrm{molL}^{-1}}  is reduced to  \mathrm{2.5 \mathrm{molL}^{-1}} in

Option: 1

10 min


Option: 2

20 min


Option: 3

30 min


Option: 4

40 min 


Answers (1)

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For a first order reaction,
\mathrm{t=\frac{2.303}{k} \log \frac{[A]_0}{[A]} }
where   \mathrm{[A]_0= }  initial concentration of reactant
\mathrm{[A]_0= } present concentration of reactant
\mathrm{k= } rate constant \mathrm{=0.0693 \mathrm{~min}^{-1} }
So, time required for concentration to change from \mathrm{20 \mathrm{~mol} \mathrm{~L}^{-1} }  to \mathrm{2.5 \mathrm{~mol} \mathrm{~L}^{-1} }
\mathrm{ t=\frac{2.303}{0.0693} \log \left[\frac{20}{2.5}\right] }
\mathrm{ t \approx 30 \mathrm{~min} }.

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Ajit Kumar Dubey

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