Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • The rate constant, the activation energy and the Arhenius parameter (A) of a chemical reaction at  <img alt="25^{\circ} \mathrm{C}" src="https://entrancecorner.oncodecogs.com/gif.latex?25%5E%7

The rate constant, the activation energy and the Arhenius parameter (A) of a chemical reaction at  25^{\circ} \mathrm{C}  are  3.0 \times 10^{-4} \mathrm{sec}^{-1}, 104.4 \mathrm{~kJ} \mathrm{~mol}^{-1}  and  6.0 \times 10^{-4} \mathrm{sec}^{-1}  respectively the value of the rate constant  \mathrm{T \rightarrow \infty}  is

Option: 1

3.0 \times 10^{-4} \mathrm{sec}^{-1} \\


Option: 2

6.0 \times 10^{-4} \mathrm{sec}^{-1} \\


Option: 3

10.4 \times 10^{-4} \mathrm{sec}^{-1}


Option: 4

None of the above


Answers (1)

best_answer

As per Arrhenius equation, rate constant \mathrm{K}=\mathrm{Ae} \mathrm{e}^{-\mathrm{E} / \mathrm{RT}}
\mathrm{ \text { At } T \rightarrow \infty, E_a / R T \rightarrow 0 }
\mathrm{ \Rightarrow K=A e^{-E a / R T}=A e^0=A}
\mathrm{ \Rightarrow \mathrm{K}=6.0 \times 10^{-4} \mathrm{sec}^{-1}}

Posted by

Ajit Kumar Dubey

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

NTA Exam Calendar 2025 Live: JEE Main, NEET, CUET schedule to be announced soon; download at nta.ac.in
anam-khan

NTA Exam Calendar 2025: JEE Main, NEET, CUET exam dates soon
anam-khan

JEE Main, NEET, CUET 2025 Dates Live: NTA to announce exam calendar soon on nta.ac.in; latest updates

Latest Question