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The rate constants for decomposition of acetaldehyde have been measured over the temperature range \mathrm{700-1000\, K}. The data has been analysed by ploting \mathrm{ln \, k\, vs\: \frac{10^{3}}{T}} graph.
The value of activation energy for the reaction is ______ \mathrm{KJ\, mol^{-1}}.(Nearest integer)
(Given : \mathrm{R= 8.31\, J\, K^{-1}\, mol^{-1}})


 

Option: 1

154


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

As we have learnt,

\mathrm{K=A e^{-E a / R T}}
\mathrm{\Rightarrow \ln K =\ln A-\frac{E a}{R}\left(\frac{1}{T}\right)}
\mathrm{\Rightarrow \ln K =\left(\frac{-E a}{R}\right) \frac{1}{T}+\ln A }

\mathrm{\therefore\; \frac{E a}{10^{3} R} =18.5}

\mathrm{\Rightarrow \: E a =18.5 R \times 10^{3}}
              \mathrm{=153.75 \mathrm{~kJ} \, \mathrm{mol^{-1}}}

Hence, the answer is 154 .

Posted by

Ritika Harsh

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