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The rate of a reaction aA +bB Products, is given by  \mathrm{k[A]^{n} [B]{^{m}}}. On doubling the concentration of A and halving the concentration of B the rate of reaction changes by 

 

Option: 1

\mathrm{1 / 2^{(m+n)} }


Option: 2

\mathrm{2^{(n+m)} }


Option: 3

\mathrm{2^{(n \cdot m)} }


Option: 4

\mathrm{m+n}


Answers (1)

best_answer

\mathrm{ rate_1=k[A]^{\mathrm{n}}[\mathrm{B}]^{\mathrm{m}} }


\mathrm{ rate_2=k[2 \mathrm{A}]^{\mathrm{n}}[\mathrm{B} / 2]^{\mathrm{m}}}

=\mathrm{k}[\mathrm{A}]^{\mathrm{n}}[\mathrm{B}]^{\mathrm{m}} 2^{\mathrm{n}}(1 / 2)^{\mathrm{m}}

\\ =\mathrm{k}[\mathrm{A}]^{\mathrm{n}}[\mathrm{B}]^{\mathrm{m}} \times 2^{(\mathrm{n}-\mathrm{m})} \\\\ =\mathrm{ rate _1 \times 2^{(\mathrm{n}-\mathrm{m})}}
 Hence, (3) .

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manish

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