Get Answers to all your Questions

header-bg qa

The rate of a reaction increases by 3 times when the temperature is raised from 300 K to 310 K. If K is the rate constant at 300 K, then the rate constant at 310 K will be equal to

Option: 1

K/3


Option: 2

3K 


Option: 3

9K 


Option: 4

k


Answers (1)

best_answer

Rate constant

=\mathrm{K}^{\prime}=3^{(\Delta \mathrm{T} / 10)} \mathrm{K}
\mathrm{ \Rightarrow K^{\prime}=3^{(310-300) / 10} K }
\mathrm{ \Rightarrow K^{\prime}=3 K }.

Posted by

Divya Prakash Singh

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE