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  • The ratio of de-Broglie wavelength of an particle and a proton accelerated from rest by the same potential is <im

The ratio of de-Broglie wavelength of an \alpha particle and a proton accelerated from rest by the same potential is \frac{1}{\sqrt{m}}, the value of m is-

Option: 1

16


Option: 2

4


Option: 3

2


Option: 4

8


Answers (1)

best_answer

\begin{aligned} & \frac{\lambda_\alpha}{\lambda_{\mathrm{p}}}=\frac{\frac{\mathrm{h}}{\sqrt{2 \mathrm{~m}_\alpha \mathrm{q}_\alpha \mathrm{v}}}}{\frac{\mathrm{h}}{\sqrt{2 \mathrm{~m}_{\mathrm{p}} \mathrm{q}_{\mathrm{p}} \mathrm{v}}}} \\ & \frac{\lambda_\alpha}{\lambda_{\mathrm{p}}}=\sqrt{\frac{1}{8}} \\ & \mathrm{M}=8 \end{aligned}

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