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  • The ratio of longest wavelength and the shortest wavelength observed in the five spectral series of emission spectrum of hydrogen isOption: 1 <img al

The ratio of longest wavelength and the shortest wavelength observed in the five spectral series of emission spectrum of hydrogen is

Option: 1

\frac{4}{3}


Option: 2

\frac{525}{376}


Option: 3

25


Option: 4

\frac{900}{11}


Answers (1)

best_answer

Shortest wavelength comes from \mathrm{n_1=\infty} to \mathrm{n_2=1}
and longest wavelength comes from \mathrm{n_1=6} to \mathrm{n_2=5} in the given case.

Hence \mathrm{\frac{1}{\lambda_{\min }}=R\left(\frac{1}{1^2}-\frac{1}{\infty^2}\right)=R}

\mathrm{\frac{1}{\lambda_{\max }}=R\left(\frac{1}{5^2}-\frac{1}{6^2}\right)=R\left(\frac{36-25}{25 \times 36}\right)=\frac{11}{900} R }
\mathrm{\therefore \frac{\lambda_{\max }}{\lambda_{\min }}=\frac{900}{11} }

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