Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • The ratio of the masses percentages of  and <img alt="'C' and, 'O'" src="http://entrancecorner.oncodecogs.com/gif.latex?%27C%27%20

The ratio of the masses percentages of 'C' and , 'H' and 'C' and, 'O' of a saturated acyclic organic compound 'X' are 4:1  and 3:4  respectively . Then , the moles of oxygen gas required  for complete combustion of two moles of organic compound 'X'  is_____________
 

Answers (1)

best_answer

We have

Mass ratio of C:H = 4:1

Mass ratio of C:O = 3:4

Thus, mass ratio of C:H:O = 12:3:16

Mass ratio of C:H:O = 1:3:1

Thus, empirical formula = CH3O

Now, since (CH3O)n is saturated acyclic. Hence only possible value of n is 2.

Thus, the compound is C2H6O2.

Now, the reaction occurs as follows:

\mathrm{C}_{2} \mathrm{H}_{6} \mathrm{O_{2}}+\: \frac{5}{2}\mathrm{O}_{2} \rightarrow 2 \mathrm{CO}_{2}+3 \mathrm{H}_{2} \mathrm{O}

Thus, 5 moles of O2 are required for combustion of 2 moles of the organic compound.

 

Posted by

Kuldeep Maurya

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

BTech aspirant from north-east or UT? Apply for CSAB NEUT counselling 2025 today
anam-khan

JoSAA round 2 cut-off 2025 out; BTech closing ranks for top engineering courses at IITs
anam-khan

Goa Engineering Admission 2025: 1,415 eligible for BE seats; merit list on June 27

Latest Question