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  • The reaction <img alt="\mathrm{N}_{2} \mathrm{O}_{5}(\mathrm{~g}) \rightarrow \mathrm{N}_{2} \mathrm{O}(\mathrm{g})+2 \mathrm{O}_{2}(\mathrm{~g})" src="https://entrancecorner.oncodecogs.com/gif.lat

The reaction \mathrm{N}_{2} \mathrm{O}_{5}(\mathrm{~g}) \rightarrow \mathrm{N}_{2} \mathrm{O}(\mathrm{g})+2 \mathrm{O}_{2}(\mathrm{~g}) is a first order reaction with rate constant \mathrm{2772 \times 10^{-6} \mathrm{~Hz}}.starting with 1 mole of \mathrm{\mathrm{N}_{2} \mathrm{O}_{5}} in 2 litre vessel, find the conc of \mathrm{\mathrm{N}_{2} \mathrm{O}_{5}} after 4 minutes 10 seconds when the reaction is allowed to take place at constant pressure and \mathrm{27^{\circ} \mathrm{C}}?

Option: 1

0.0125 M


Option: 2

0.125 M


Option: 3

0.150 M


Option: 4

0.250 M


Answers (1)

best_answer

\mathrm{t_{1 / 2}=\frac{0.693}{k} }
\mathrm{t_{1 / 2}=\frac{0.693}{2772} \times 10^{6} }
\mathrm{t_{1 / 2}=\frac{1000}{4}=250 \mathrm{~s}}

Since volume is changing, therefore half -life should be defined on the basis of moles, so moles of R remaining offer 4 minutes 10 seconds \mathrm{(=250\, s)}. AIso final volume of the container

\mathrm{V_{f}=\frac{n_{f}}{n_{i}} \times V_{i}=\frac{0.5+1.5}{1} \times 2=4 \mathrm{~L}}
Final Conc. of \mathrm{\mathrm{N}_{2} \mathrm{O}_{5}=\frac{0.5}{4}=0.125 \mathrm{~M}}

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Nehul

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