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 The reaction of zinc with excess of aqueous alkali, evolves hydrogen gas and gives : 

Option: 1

\mathrm{\mathrm{Zn}(\mathrm{OH})_{2}}


Option: 2

\mathrm{\mathrm{ZnO}}


Option: 3

\mathrm{\left[\mathrm{Zn}(\mathrm{OH})_{4}\right]^{2-}}


Option: 4

\mathrm{\left[\mathrm{ZnO}_{2}\right]^{2-}}


Answers (1)

best_answer

The reaction will be 
                                   sodium zincate 
\mathrm{Zn+2NaOH\rightarrow Na_{2}ZnO_{2}+H_{2} \uparrow}
                                          \downarrow
                                       \mathrm{\left [ ZnO_{2} \right ]^{2-}}

It is preparation method of \mathrm{H_{2}.}

Option (4) is correct. 

Posted by

Pankaj Sanodiya

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