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The required height of a TV tower which can cover the population of 6.03 lakh is \mathrm{h}. If the average population density is 100 per square \mathrm{km} and the radius of earth is 6400 \mathrm{~km}, then the value of \mathrm{h} will be___________ \mathrm{m}.

Option: 1

150


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\mathrm{\frac{\text { Population }}{\text { (Area of Range)}}= population \: \: \: density }

\mathrm{\frac{6.03 \times 10^5}{\pi(2 R \mathrm{~h})}=100 \quad(\because Range =\sqrt{2 R h})}

\mathrm{h=0.15 \mathrm{~km}=150 \mathrm{~m}}

Posted by

Irshad Anwar

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