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The resistivity of a 0.8M solution of an electrolyte is 5 \times 10^{-3} \Omega \mathrm{cm}. Its molar conductivity is \times\; 10^4 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}
(Nearest integer)

Option: 1

25


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\begin{aligned} & \mathrm{K}=\frac{1}{5 \times 10^{-3}} \\ & \wedge_{\mathrm{m}}=\mathrm{K} \times \frac{1000}{\mathrm{M}}=\frac{1}{5 \times 10^{-3}} \times \frac{1000}{0.8} \\ & =\frac{1000}{40} \times 10^4=25 \times 10^4 \end{aligned}

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