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The solution of the equation 

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@Santhosh

\\\frac{d^2y}{dx^2}=e^{-2x}\\integrate\:both\:side\\\frac{dy}{dx}=\int e^{-2x}dx=-\frac{1}{2}e^{-2x}+c\\again\:integrate\\y=\frac{1}{4}e^{-2x}+cx+d

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himanshu.meshram

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